Answer:
Step-by-step explanation:
(3x+1)(x-3)-(2-2x^2-3x)
3x^2+x-9x-3-2+2x^2+3x
3x^2+2x^2+x-9x+3x-3-2
5x^2-5x-5
the constant term in the simplified expression is -5.
Answer:
Pretty sure it's C
Step-by-step explanation:
For inverse functions, I do the opposite operation
the only logical inverse function I see working in this expression would be C
divide the 5 from 5x and add the 3
Also, subtract the f(x) on both sides to get the "- y"
so, you get : 5/x + 3 = - y (f(x) is just "y")
Answer:
a) see the plots below
b) f(x) is exponential; g(x) is linear (see below for explanation)
c) the function values are never equal
Step-by-step explanation:
a) a graph of the two function values is attached
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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).
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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.
In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.
Answer:
c. S'(3, 1), T'(1, -1), U'(0, 1)
Step-by-step explanation:
Reflection across the y-axis negates the x-coordinate, so is equivalent to the transformation ...
(x, y) ⇒ (-x, y)
Reflection across the horizontal line y=c is equivalent to the transformation ...
(x, y) ⇒ (x, 2c-y)
So, the combined reflections are equivalent to the transformation ...
(x, y) ⇒ (-x, 4 -y)
Then we have ...
S(-3, 3) ⇒ S'(-(-3), 4-3) = S'(3, 1)
T(-1, 5) ⇒ T'(-(-1), 4-5) = T'(1, -1)
U(0, 3) ⇒ U'(-(0), 4-3) = U'(0, 1) . . . . matches choice C