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1 year ago

Solve for I when 3/5 +I-1/15

Mathematics

1 answer:

Ugo [173]1 year ago

4 0

Answer:

23 over 15 or 1.533

Step-by-step explanation:

Group like terms:

1+(3/5+-1/15)

Find LCD:

1+9/15+-1/15

Combine numerators:

15/15+8/15

And you get 23/15

Simplified:1 8/15

Decimal: 1.533

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What’s the answer to this question

Nataly_w [17]

$6 x^{3}$ + 3x + 5
- $2x^{2}$ + 6x + 5
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4x - 3 + 0

5 0

2 years ago

Scientific notation 20,000+3,400,000= an example to would be helpful

Viefleur [7K]

20 000 is as much as 20 * 1 000, so we can write it as: 20 * 10^3
3 400 000 is as much as 34 * 100 000, so we can write it as: 34 * 10^5

The sum in scientific notation would look like this:

20 * 10^3 + 34 * 10^5

I hope that's what you meant :)

4 0

2 years ago

Read 2 more answers

In a sample of 70 stores of a certain company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi

uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$n = 70, p = \frac{62}{70} = 0.886$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.

We need at least n stores.

n is found when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}$