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2 years ago

14

Of the 500 cars displayed in a certain car dealer, 7 percent are blue and 4 percent are red. The number of blue cars in the car

dealer are what percent greater than the number of red cars?

1 answer:

solong [7]2 years ago

7 0

Answer:

70 percent

Step-by-step explanation:

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Without doing any calculations, how can you use the given information to tell which animal mo the fastest? The moves much th mov

erik [133]

You can tell which animal is faster by pacing

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2 years ago

PLEASE HELP FOR BRAINLIEST! :)

elena-s [515]

Give that man a brainliest

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2 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

So

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

8 0

8 months ago

If an image of a triangle is congruent to the pre-image, what is the scale factor of the dilation?

r-ruslan [8.4K]

The scale factor of the dilation is 1 because the image and pre-image share the SAME everything (lengths, area, etc.). So if you multiply one of the image’s length by any number other than one, the pre-image will change.

3 0

2 years ago

A certain microprocessor requires either 2, 3, 4, 8, or 12 machine cycles to perform various operations. Twenty-five percent of

myrzilka [38]

Answer:

The average number of machine cycles per instruction for this microprocessor is 5.8.

Step-by-step explanation:

To find the average number of machine cycles per instruction for this microprocessor, we multiply each number of cycles for it's relative frequency.

We have that:

25% require 2 cycles.

20% require 3 cycles.

17.5% require 4 cycles.

12.5% require 8 cycles.

25% require 12 cycles.

So the average number is:

$M = 0.25*2 + 0.2*3 + 0.175*4 + 0.125*8 + 0.25*12 = 5.8$

3 0

2 years ago