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3 years ago

Find a quadratic function that includes the set of values below.

Mathematics

1 answer:

Hoochie [10]3 years ago

8 0

Answer:

there you go . Good luck plz mark me brainliest .

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What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

3 years ago

PLEASE HELP I NEED TI GO TO BED AND ITS 12 am! Select the ordered pairs that are solutions to the inequality 2x-3y greater than

max2010maxim [7]

(8,1);((-2,-6)

2•8-3•1>=12
16-3>=12
13>=12

2•(-2)-3(-6)>=12
-4+18>=12
14>=12

5 0

3 years ago

Read 2 more answers

Given a≠±b and a^2−b^2 / a+b =12, find a−b.

Olegator [25]

Answer:

a-b=12

Step-by-step explanation:

(a²-b²)/(a+b) = 12

(a-b)(a+b)/(a+b)=12

a-b=12

3 0

3 years ago

From the set (76, 77, 78), use substitution to determine which value of x makes the equation true

jeyben [28]

Answer:

The answer is C.

Step-by-step explanation:

Multiply 4 by 76, 77, and 78.

4 * 76 = 304

4 * 77 = 308

4 * 78 = 312

304 = 304, so C is the correct answer.

Hope this helps!

7 0

3 years ago

Need some help with this please

saveliy_v [14]

-0.83 for it’s the lowest number

5 0

3 years ago