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3 years ago

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5. (07.01 MC) If the sin 90° = 1, then the cos 0° = _____. (1 point) 0, because the angles are complementary 1 over 2, because t

he angles are complementary square root 3 over 2, because the angles are complementary 1, because the angles are complementary

1 answer:

Luba_88 [7]3 years ago

4 0

Answer:

0

Step-by-step explanation:

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Find 3 rational number between: 1) -5 and -6 2)

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Answer:

3 rational numbers between -5 and -6 include -5.6, -5.7, and -5.1.

Step-by-step explanation:

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Plz help me 20points

Alexandra [31]

Answer:

20 according to me. I am sorry if I'm wrong

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Rama09 [41]

Answer:

c

Step-by-step explanation:

1 2/3 in improper form is -> 5/3

4 1/6 in improper form is -> 25/6

5/3 is equal to-> 10/6

so.. 25 divided by 10 equals 2.5

so to fill the cylinder you'll need 3 sm cylinders (u can't only have a half of a cilinder)

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3 years ago

If you answer a question put the number of the question in your answer. Thanks

Veronika [31]

Answer:

You'll find the answer below each.

Step-by-step explanation:

1-4 you can use this formula: $V=l*h*w$

1.

$V=l*w*h\\V=(6ft)(4ft)(1ft)\\V=24ft^3$

2.

$V=l*h*w\\V=(2yd)(\frac{1}{2}yd )(2yd)\\V=2yd^3$

3.

$V=l*h*w\\V=(12\frac{1}{2}mm)(3mm)(4mm)\\V=150mm^3$

4.

$V=l*h*w\\V=(2cm)(8.5cm)(2cm)\\V=34cm^3$

5-7 you need these 2 formulas: $A=\frac{bh}{2}$ and $V=Bh$ or you can use one formula which is: $V=\frac{bh}{2}*h$

Let me explain. The first formula is for finding the area of the base of the triangle and the second formula is for finding the volume of the prism using the area previously mentioned. The first h is with respect to the triangle and the second h is with respect to the prism.

5.

$V=\frac{bh}{2}*h\\V=\frac{(8in)(6in)}{2}* 18in\\V=\frac{48in^2}{2}*18in\\ V=48in^2*9in\\V=432in^3$

6.

$V=\frac{bh}{2}*h \\V=\frac{(11m)(5m)}{2}*35m \\V=\frac{55m^2}{2}*35m\\ V=\frac{1925m^3}{2}\\ V=962.50m^3$

7.

$V=\frac{bh}{2}*h \\V=\frac{(5mm)(8mm)}{2}*12mm\\V=\frac{40mm^2}{2}*12mm\\ V=40mm^2*6mm\\V=240mm^3$

For the last one, we have a special case.

This formula is a bit odd and long.

$V=\frac{1}{4}h(\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}$

a=8yd

b=15yd

c=17yd

h=11yd

$V=\frac{1}{4}(11yd)(\sqrt{-(8yd)^4+2[(8yd)(15yd))]^2+2[(8yd)(17yd)]^2-(15yd)^4+2[(15yd)(17yd)]^2}$ $-(17)^4$

As you can see this is long. I'll just jump to the answer.

Answer: $660yd^3$

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When we use the Distributive

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Answer: 12x + 6

Step-by-step explanation:

In Distributive property, you multiply each of the numbers in the parentheses by the outside number.

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