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Hitman42 [59]
3 years ago
14

Which molecule is important in regulating cell membrane fluidity?

Biology
2 answers:
eduard3 years ago
8 0

Answer:

cholesterol plays a distinct role in determining membrane fluidity.

AlekseyPX3 years ago
7 0

Answer:

cholesterol

Explanation:

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PLS HELP! Will give brainlest Worth 10 points. Which level of organization in living things does this image represent? A. Organ
BabaBlast [244]

Answer:

organ system is correct answer

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2 years ago
When does the cell cycle start at? When does it end?
disa [49]

The D period refers to the stage between the end of DNA replication and the splitting of the bacterial cell into two daughter cells. In cells with a nucleus, as in eukaryotes, the cell cycle is also divided into three periods: interphase, the mitotic (M) phase, and cytokinesis.

3 0
3 years ago
In a species of bird, the allele for the striped trait is recessive to the allele for the speckled trait. Suppose that a coastal
mylen [45]

Answer:

The answer is "0.42"

Explanation:

Please find the complete question in the attached file.

Coastal community striped allele intensity = q = 0.62

Landlocked community, strip intensity allele=q'=0.40

Its eliminated allele frequency for movement = q"=0.42 \ in \ indoorscommunity And now in the sturdy vineyard optimum communities, genotype frequency of stripped characteristic (heterozygous device) in coasts=q_2=0.39

Heritable (striped) allele frecency:

\to q=\sqrt{q_2}

      =\sqrt{0.39} \\\\ =0.624 \\\\ =0.62

(round up to the closest cent) is therefore the only frequency of coastal people.

The genome of pulling function in host population= q'_2=0.16 Heterozygous feature regularly.

Therefore the inland community rate of recessed (striped), allele rate:

\to q'= \sqrt{q'_{2}}= \sqrt{0.16}=0.40

Following migration;

Its percentage of coastal migrants:

m=10\% \\\\

   = \frac{10}{100} \\\\= 0.1

Coastal population Non-immigrant percentage of coastal residents:

=1- m\\\\=1-0.1\\\\ =0.9

Stripping coastal community of allele rate after immigration:

(q")=\text{(stripping of migrant only freq)}\times (m)+\text{(stripping allele baud rate for non-immigrants)} \times ( 1-m)

       = [q \times m]+[[q' \times(1-m)]\\\\=(0.62 \times 0.1)+(0.40 \times 0.9)\\\\=0.062+ 0.36\\\\=0.422\\\\=0.42

8 0
3 years ago
Question 15 (1 point)
lianna [129]

Answer:

The answer is C (UAAGCUCGU)

Explanation:

T is replaced by U in RNA and A and U "bind". In this case, we're looking for the complementary RNA strand, so all terms are opposite; G becomes C, A becomes U, etc.

8 0
3 years ago
Why are astrologers not considered to be a scientist
grigory [225]
Because astrologers don't use tools , don't observe the planet.
6 0
3 years ago
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