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aleksklad [387]
2 years ago
12

Determine maximum and minimum value of the function y=4x-x^2 +3

Mathematics
1 answer:
Tom [10]2 years ago
3 0

Answer:

y =  -  {x}^{2}  + 4x + 3 \\ x =   - \frac{b}{2a}  \\ x =   - \frac{4}{2( - 1)} \\ x = 2 \\ y = f(2) = 4(2) -  {(2)}^{2}  + 3 \\ y = 7 \\  \therefore \: maximum \: at \binom{2}{7}

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