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3 years ago

Determine maximum and minimum value of the function y=4x-x^2 +3

Mathematics

1 answer:

Tom [10]3 years ago

3 0

Answer:

$y = - {x}^{2} + 4x + 3 \\ x = - \frac{b}{2a} \\ x = - \frac{4}{2( - 1)} \\ x = 2 \\ y = f(2) = 4(2) - {(2)}^{2} + 3 \\ y = 7 \\ \therefore \: maximum \: at \binom{2}{7}$

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Will mark as brainliest

lapo4ka [179]

Answer:

-1 + 2 = 1

1 + (-2) = -1

-1 - 2 = -3

1 - (-2) = 3

Step-by-step explanation

When you subtract use keep change change

Rule 1 when you add : If the signs are the same add the numbers and take the sign of the bigger number.

Rule 2 when you add : If the signs are different subtract the numbers and take the sign of the bigger number.

I wanted to help you understand and i hope i did that!

8 0

3 years ago

Solve the following inequality for X <br> -7.3x < -21.9x + 73

Aleonysh [2.5K]

Answer:

X=®™✓©™[[

Step-by-step explanation:

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7 0

3 years ago

What is the soultion to the linear system y=2x and y=x+4

uranmaximum [27]

Answer:

x = 4; y = 8

Step-by-step explanation:

y=2x

y=x+4

2x = x + 4

x = 4

y = 2x = 2(4)

y = 8

Solution: x = 4; y = 8

5 0

2 years ago

Which equation has the same value as 46.5-17.32

svetlana [45]

Where are the options

7 0

3 years ago

What is the probability of rolling a dice at most 3 times until a 6 occurs

IRISSAK [1]

Answer:

Probablity of getting six in at most three roll= 0.199.

Step-by-step explanation:

Given: Dice rolled at most 3 times untill a 6 occurs.

First, finding the probablity of getting 6 in a dice if rolled once.

Probablity= $\frac{chances\ of\ occurance}{Total\ number\ of\ event}$

We know, dice have six side, therefore, total number of event will be 6.

∴ Probablity of getting six in one roll= $\frac{1}{6}$

As given, Dice is rolled at most 3 times.

Now, finding the probablity of getting 6 in a dice if rolled 3 times.

∴ Probablity of getting six in three roll= $\frac{1}{6}+(\frac{1}{6})^{2} +(\frac{1}{6})^{3}$

⇒ Probablity of getting six in three roll= $\frac{1}{6}+\frac{1}{36} +\frac{1}{216}$

Taking LCD 216

⇒Probablity of getting six in three roll= $\frac{1\times 36+ 6\times 1+1}{216}$

⇒Probablity of getting six in three roll= $\frac{43}{216}$

∴Probablity of getting six in three roll=0.199

3 0

4 years ago