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Sphinxa [80]
3 years ago
14

7.

Physics
1 answer:
Rom4ik [11]3 years ago
4 0
4
I think that’s correct
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A region of space in which a test charge experiences a force is referred to as
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Answer: The correct answer is- Field.

Explanation -

The modified space around a charged particle is known as electric field.

The strength of electric field at a point is calculated as the force experienced by a unit test charge present at that point.


Thus, a region of space in which a test charge experiences a force is referred to as Field.

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3 years ago
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How does the medium which a sound wave travels, affect a sound
arlik [135]

The density of <u>a medium</u> is the second factor that <u>affects the speed of sound.</u>

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3 years ago
A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0
Elodia [21]

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

8 0
3 years ago
A 0.030 kg lead bullet hits a steel plate, both initially at 20?C. The bullet melts and splatters on impact. Assume that 80% of
Dmitry_Shevchenko [17]

Answer:

(a). The required is 1871.2 J.

(b). The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Explanation:

Given that,

Mass of bullet = 0.030 kg

Temperature = 20°C

(a). We need to heat required to increase the temperature of the lead bullet and melt it

Using formula of heat

Q=mS\Delta T+mL

Where, m = mass of lead bullet

S = specific heat

L = latent heat

T = Temperature

Put the value into the formula

Q=0.030\times130\times(327.5-20)+0.030\times22400

Q=1871.2\ J

The required is 1871.2 J.

(b). Assume that 80% of the bullet’s kinetic energy goes into increasing its temperature and then melting it

We need to calculate the energy

Q=\dfrac{1871.2}{0.8}

Q=2339 J

We need to calculate the speed the lead bullet

Using formula of speed

K.E=Q

\dfrac{1}{2}mv^2=2339

v^2=\dfrac{2339\times2}{0.030}

v=\sqrt{\dfrac{2339\times2}{0.030}}

v=394.8 = 395\ m/s

The speed the lead bullet is 395 m/s.

(c). The 20% of energy must have gone into collision between steel plate and bullet.

Hence, This is the required solution.

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3 years ago
A spring whose stiffness is 1140 n/m has a relaxed length of 0.51 m. if the length of the spring changes from 0.26 m to 0.79 m,
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A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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4 years ago
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