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Amiraneli [1.4K]

3 years ago

9

A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0

x 10^5 Pa. What are the correct values for heat and work for the piston?

1 answer:

Elodia [21]3 years ago

8 0

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

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worty [1.4K]

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(12 points) When forces are UNBALANCED on an object, the object could: (Choose all that apply)

charle [14.2K]

As per Newton's law when unbalanced force is acting on the object

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4 years ago

7. An outfielder throws a baseball to the first baseman at a speed of 19.6

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3 years ago

What force must be provided to accelerate a 64-lb object upward at a rate of 2 ft/s2? (Use g = 32 ft/s2.)

vovikov84 [41]

Answer:

The force that must be provided to accelerate the object = 302.196 N

Explanation:

<em>Force</em>: Force can be defined as the product of mass and acceleration. The S.I unit of force is Newton (N).

Ft - W = ma............ Equation 1

Ft = W + ma .......... Equation 2

Where Ft = force provided, W = weight of the object, m= mass of the object, a = acceleration of the object.

<em>Given: mass = 64 lb, g = 32 ft/s² a = 2 ft/s²</em>

<em>Conversion: (i) from 64 pounds to Kg = 64/2.2046</em>

<em> = 29.03 kg</em>

<em> (ii) from 2 ft/s² to m/s² = 0.3048 × 2 = 0.6098 m/s²</em>

<em> (iii) from 32 ft/s² to m/s² = 0.3048×32 = 9.8 m/s².</em>

and W = mg = 29.03 × 9.8 = 284.494 N,

Substituting these values into equation 2,

Ft = 284.494 + 29.03×0.6098

Ft = 284.494 + 17.7

Ft = 302.196 N

Therefore, the force that must be provided to accelerate the object = 302.196 N

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4 years ago

A cart of mass 20 kg, initially at rest, is pushed with a net force of 40 N on a flat surface. If the cart is pushed 5 m, what i

bixtya [17]

Using the theorem of kinetic energy
1/2mVf² - 1/2mVi²= WF + Wp, Wp=0
WF = F. AB, AB=5m and F= 40N, m=20kg
so the final kinetic is KEf= 1/2mVf² = WF =<span>F. AB= 40*5=200J
</span>
the final velocity is 1/2mVf² <span>=200, implies Vf= sqrt(20)=2sqrt(5)m/s</span>

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3 years ago