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3 years ago

The movement of particles from high to low concentration. True or False

Physics

1 answer:

Digiron [165]3 years ago

8 0

Question:

Diffusion is the movement of particles from high to low concentration. True or False

Answer:

True.

Explanation:

Diffusion is a process that allows the movement of substance or particles in and out of cells through a semipermeable membrane.

Diffusion is a process that allows the spread or movement of particles from the region of higher concentration to a region of lower concentration through a semipermeable membrane.

Diffusion only occurs in gases and solution but not in solids, it also occurs only where particles can move freely.

Note: When particles move from the region of higher concentration to a lower concentration, it gives room for even, uniform and random distribution of particles.

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Explain why water boiling in a container stops<br>boiling momentarily when the lid is removed

Dmitriy789 [7]

Answer:

It's because it tips over the threshold from nucleate boiling, which we can see, to convection boiling, which we can't. ... Even if the steam stayed in the pot, it would still stop boiling when you removed the heat. The steam and water in a liquid/vapour mixture are at the same temperature (100ºC).

Explanation:

8 0

3 years ago

I need help in physics please help me

artcher [175]

The first step is to represent the vectors shown in the image in Cartesian coordinates.

For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)

To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

$x = 4.8sin(22)i\\\\y = 4.8cos(22)(-j)$

So:

$C = 4.8sin(22) i + 4.8cos(22)(-j)\\\\C = 1.798\ i - 4.450\ j$

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)

So:

$x = 5.6cos(33)(-i)\\\\y = 5.6 sin(33)(-j)$

So:

$B = 5.6cos(33)(-i) + 5.6sin(33)(-j)\\\\B = -4.696\ i - 3.05\ j$

Finally the sum of B + C is made component by component in the following way:

$F = (-4.696 +1.798)i + (-4.450 - 3.05)j\\\\F = -2.898\ i - 7.5\ j$

Finally the magnitude of f is:

$|F| = \sqrt{(-2,898)^2 + (-7.5)^2}$

| F | = 8.04

3 0

3 years ago

A wire carries a current of 4.1 A. How many electrons per second are passing any cross sectional area of the wire? Enter your an

aivan3 [116]

To solve this problem it is necessary to apply the concepts related to Current and Load.

The current in terms of the charge of an electron can be expressed as

$i = \frac{q}{t}$

Where,

q = Charge

t = time

At the same time the Charge is the amount of electrons multiplied by the amount of these, that is

q = ne

Replacing in the first equation we have to

$i = \frac{q}{t}$

$i = \frac{ne}{t}$

Clearing n,

$n = \frac{it}{e}$

Here the time is one second then

$n = \frac{i}{e}$

$n = \frac{4.1}{1.6*10^{-9}}$

$n = 2.56*10^{19}electrons$

Therefore the number of electrons per second are passing any cross sectional area of the wire are $2.56*10^{19}electrons$

3 0

3 years ago

How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field in

Ugo [173]

Answer:

Explanation:

radius of the solenoid, r = 0.05 m

length of the solenoid, l = 0.39 m

Magnetic field of the solenoid, B = 2 x 10^-5 T

Number of turns, N = 200

The magnetic field of the solenoid is given by

$B=\mu _{0}ni$

where, i be the current and n be the number of turns per unit length

n = N / l = 200 / 0.39 = 512.8

$2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i$

i = 0.031 A

3 0

3 years ago

The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor

Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0

3 years ago