Answer:
It's because it tips over the threshold from nucleate boiling, which we can see, to convection boiling, which we can't. ... Even if the steam stayed in the pot, it would still stop boiling when you removed the heat. The steam and water in a liquid/vapour mixture are at the same temperature (100ºC).
Explanation:
The first step is to represent the vectors shown in the image in Cartesian coordinates.
For the vector C we have a magnitude of 4.8 and an angle 22 ° with the axis -y (direction j)
To write this vector in Cartesian coordinates we must find its component in x (address i) and in the y axis.

So:

For Vector B we have a magnitude of 5.6 and an angle of 33 with the -x axis (-i direction)
So:

So:

Finally the sum of B + C is made component by component in the following way:

Finally the magnitude of f is:

| F | = 8.04
To solve this problem it is necessary to apply the concepts related to Current and Load.
The current in terms of the charge of an electron can be expressed as

Where,
q = Charge
t = time
At the same time the Charge is the amount of electrons multiplied by the amount of these, that is
q = ne
Replacing in the first equation we have to


Clearing n,

Here the time is one second then



Therefore the number of electrons per second are passing any cross sectional area of the wire are 
Answer:
Explanation:
radius of the solenoid, r = 0.05 m
length of the solenoid, l = 0.39 m
Magnetic field of the solenoid, B = 2 x 10^-5 T
Number of turns, N = 200
The magnetic field of the solenoid is given by

where, i be the current and n be the number of turns per unit length
n = N / l = 200 / 0.39 = 512.8

i = 0.031 A
Answer:
The new height the ball will reach = (1/4) of the initial height it reached.
Explanation:
The energy stored in any spring material is given as (1/2)kx²
This energy is converted to potential energy, mgH, of the ball at its maximum height.
If the initial height reached is H
And the initial compression of the spring = x
So, mgH = (1/2)kx²
H = kx²/2mg
The new compression, x₁ = x/2
New energy of loaded spring = (1/2)kx₁²
And the new potential energy = mgH₁
mgH₁ = (1/2)kx₁²
But x₁ = x/2
mgH₁ = (1/2)k(x/2)² = kx²/8
H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)