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Dovator [93]
3 years ago
8

PLEASE HELP WILL MARK BRAINLIEST NEED HELP ASAP

Mathematics
2 answers:
zheka24 [161]3 years ago
7 0

Answer:

only one

Step-by-step explanation:

aliya0001 [1]3 years ago
3 0

Answer:

1

Step-by-step explanation:

only one straight line can be passed through two points

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A rectangle has a width of 6 units and a length of 2x+8 units. If the area is 108 units squared, what is the value of X?
4vir4ik [10]

Answer:

x = 5 units

Step-by-step explanation:

Hello!

We know that the area of a rectangle is the length multiplied by the width.

  • The length is given as 6
  • The width is given as 2x + 8
  • The area is given as 108

We can simply create an expression to solve for x.

Solve:

  • Area = length x width
  • 108 = 6(2x + 8)
  • 108 = 12x + 48
  • 60 = 12x
  • x = 5

The value of x is 5 units.

7 0
2 years ago
P{lease help me solve this. Will give brainliest. I cant figure out what to do here
bulgar [2K]

Answer:

Step-by-step explanation:

x=81

63+36+x=180

99+x=180

99+81=180

y and z both equal 81

13+y+z=180

180-13=167

167/2 is 83.5

13+83.5+83.5

13+167

180

6 0
4 years ago
16, 24, 25, 26, 24, 16, 27, 24. 16. 26. x
dedylja [7]

Step-by-step explanation:

i do believe the answer is 18

5 0
3 years ago
Read 2 more answers
What is 4c+2c+6? I can’t figure this out with my daughter
earnstyle [38]

Answer:

6c+6

Step-by-step explanation:

4c+2c+6

4+2 equals 6 and add the c but since on is with a letter and one is not you can't add them so your answer stays as 6c+6

5 0
4 years ago
Read 2 more answers
If DE = 37 cm and EF = 16 cm, then what are the possible lengths for DF so that DE,EF, and DF can form a triangle? Explain your
Molodets [167]

Answer:

The length of DF must be between 21 and 53.

Step-by-step explanation:

In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.

EF + DF > DE

16 + DF > 37

DF > 21

Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.

DE + EF > DF

37 + 16 > DF

53 > DF

With these two in mind, we know that DF must be between 21 and 53

6 0
4 years ago
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