(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
t^3-t^2-2t+t^2-t-2
t^3+-3t-2
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
Answer:
-6p^5+48p
Step-by-step explanation:
-6p (p^4- 8)= -6p^5+48p
A: 1
B: 2
C: 4
D: 5
Total = 1 + 2 + 4 + 5 = 12
C:total = 4/12 = 1/3
A full circle has 360 deg.
1/3 * 360 deg = 120 deg.
Answer:
In flight, a rocket is subjected to the forces of weight, thrust, and aerodynamics. On this slide, we have removed the outer "skin" so that we can see the parts. The payload of the German V2, shown in the figure, was several thousand
Step-by-step explanation:
