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3 years ago

What is at least one more reason to use credit?

Mathematics

2 answers:

Kruka [31]3 years ago

8 0

If you plan on paying back quick?

guajiro [1.7K]3 years ago

8 0

Answer:

to build your credit score

Step-by-step explanation:

i hope this helped :)

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Please Help!!

Genrish500 [490]

Given

$a\sqrt{x+b}+c=d$

we have

$\sqrt{x+b}=\dfrac{d-c}{a}$

Squaring both sides, we have

$x+b=\dfrac{(d-c)^2}{a^2}$

And finally

$x=\dfrac{(d-c)^2}{a^2}-b$

Note that, when we square both sides, we have to assume that

$\dfrac{d-c}{a}>0$

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

$a=1,\ b=0,\ c=2,\ d=6$

and you'll have

$\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16$

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

$a=1,\ b=0,\ c=10,\ d=4$

and you'll have

$\sqrt{x}+10=4 \iff \sqrt{x}=-6$

Squaring both sides (and here's the mistake!!) you'd have

$x=36$

which is not a solution for the equation, if we plug it in we have

$\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4$

Which is clearly false

7 0

3 years ago

How many times larger is 9 × 10^9 than 3 x 10^-4

ratelena [41]

<span> 9 × 10^9
---------------- = 3 x 10^13
</span><span>3 x 10^-4

answer
3 x 10^13 times larger</span>

3 0

3 years ago

13 less than 8 times a number is the same as the number plus 1

aliya0001 [1]

8x - 13 = x + 1
Solve for x
Add 13
8x = x + 14
Subtract x
7x = 14, x = 2
Answer: the number is 2

7 0

2 years ago

A specific type of dwarfism is a genetically inherited recessive trait. based upon this pedigree. What is the probability that m

blondinia [14]

The probability of an event that has two possible outcomes is 1/2

<h3>What is Probability?</h3>

This refers to the likelihood of an event occurring and this can be found by calculating using a mathematical model.

It should be noted that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.