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zhenek [66]
3 years ago
13

What is at least one more reason to use credit?

Mathematics
2 answers:
Kruka [31]3 years ago
8 0
If you plan on paying back quick?
guajiro [1.7K]3 years ago
8 0

Answer:

to build your credit score

Step-by-step explanation:

i hope this helped :)

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{(-2, 6), (-5, -1), (3, 7), (-5, 0)}<br> Domain:<br> Range:<br> Function?
just olya [345]

{(-2, 6), (-5, -1), (3, 7), (-5, 0)}

Domain: The domain is all the x-values (-2, -5, 3, -5)

Range: The range is all the y-values (6, -1, 7, 0)

Function: It's not a function because of the x-value -5 is repeating.

6 0
3 years ago
Read 2 more answers
A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w
Rasek [7]

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

6\mleft(6.5x+2.5\mright)

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

6.5\mleft(8x+6\mright)

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

6(6.5x+2.5)+A=6.5(8x+6)

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}

The answer is:

13x+24

7 0
1 year ago
A rose garden Is formed by jolning a rectangle and a semicircle, as shown below. The rectangle Is 23 ft long and 14 ft wide.Find
Ratling [72]

Answer:

Area of the garden:

\begin{equation*} 398.93\text{ ft}^2 \end{equation*}

Explanation:

Given the below parameters;

Length of the rectangle(l) = 23 ft

Width of the rectangle(w) = 14 ft

Value of pi = 3.14

Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.

The radius(r) of the semicircle will now be;

r=\frac{d}{2}=\frac{14}{2}=7\text{ ft}

Let's now go ahead and determine the area of the semicircle using the below formula;

A_{sc}=\frac{\pi r^2}{2}=\frac{3.14*\left(7\right)^2}{2}=\frac{3.14*49}{2}=\frac{153.86}{2}=76.93\text{ ft}^2

Let's also determine the area of the rectangle;

A_r=l*w=23*14=322\text{ ft}^2

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

\begin{gathered} Area\text{ of the garden = Area of semi circle + Area of rectangle } \\ =76.93+322 \\ =398.93\text{ ft}^2 \end{gathered}

Therefore, the area of the garden is 398.93 ft^2

8 0
1 year ago
How do i find the area of this stop sign using subtraction?
Pepsi [2]
Split the object then find the 2 areas then subtract
8 0
3 years ago
Read 2 more answers
A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during
diamong [38]
The number of times the image of the octagon will coincide with the preimage during rotation is determined by:
N = R/C

where
N is the number of times the preimage coincided with the rotated image during rotation
R is the angle of rotation
C is the central angle of the regular polygon

For an octagon, the central angle is
C = 360/8 = 45

So,
N = 360 / 45 = 8

Therefore, the rotated image of the octagon will coincide with the preimage 8 times during rotation.
8 0
3 years ago
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