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lara [203]
4 years ago
9

What are 3 equivalent ratios to 7:6

Mathematics
2 answers:
galben [10]4 years ago
8 0
So it could be 14:12, 21:18 and 28:24
Amanda [17]4 years ago
5 0

Answer:  Answer: 14 : 12 , 21 : 18 and 28 : 24  

Please brainliest i answer first

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PLEASE HELP ME ANSWER THIS QUESTION PLEASEEEE I WILL GIVE BRAINLIST!!!!!!!!!!!!!!!!!!!!!
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What do you need help with???
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vfiekz [6]
First, convert the distance of a typical marathon to kilometers.
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3 years ago
A line has a slope of seven and a Y intercept of -10 what is it equation in slope intercept formI want to has a slope of seven a
SOVA2 [1]

Answer:

y=7x-10

Step-by-step explanation:

7 0
3 years ago
Find the quotient -14/7
AVprozaik [17]

The quotient is -2.


4 0
3 years ago
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
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