Answer:
Step-by-step explanation:
First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.
Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).
Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.
Si you would subtract 6x from both sides so you would have 9y=1500-6x. Then you would divide both sides by 9 and get y=166.66-6/9x. The -6/9x can be reduced to -2/3x and that is your slope or your
rise/run and the only graph that show this is the second one
Step-by-step explanation:
work is shown and pictured
