Answer:
x = y = 26 cm; z = 13 cm
Step-by-step explanation:
We can calculate the dimensions of the square base as
∛(2·8788) = 26 cm
the height of the box will be half of 26/2 which is 13 cm.
x = y = 26 cm; z = 13 cm
then the minimum area for the given volume can be calculated using what we call Lagrange multipliers, this makes it easier
area = xy +2(xz +yz)
But we were given the volume as 8788
Now we will make the partial derivatives of L to be in respect to the cordinates x, y, z, as well as λ to be equal to zero, then
L = xy +2(xz +yz) +λ(xyz -8788)
For x: we have
y+2z +λyz=0
For y we have
y: x +2z +λxz=0
For z we have 2x+2y +λxy=0............eqn(*)
For we have xyz -8788=0
If we simplify the partial derivative equation of y and x above then we have
λ = (y +2z)/(yz).
= 1/z +2/y............eqn(1)
λ = (x +2z)/(xz)
= 1/z +2/x.............eqn(2)
Set eqn(1 and 2) to equate we have
1/z +2/y = 1/z +2/x
x = y
From eqn(*) we can get z
λ = (2x +2y)/(xy) = 2/y +2/x
If we simplify we have
1/z +2y = 2/x +2/y
Then z = x/2
26/2 =13
Therefore,
x = y = 2z = ∛(2·8788)
X= 26
y = 26 cm
z = 13 cm
Answer:
8"
Step-by-step explanation:
320/40 = 8"
Answer:
x=-20
Step-by-step explanation:
add 17 to both sides
-37 + 17 =-20
<span>The number of fire-extinguisher that are required to be carried onboard motorized boats depends on the size of the boat. The main purpose of fire extinguishers is for the protection of the motor engine. Thus, For a 26 and 40 feet in length, at-least two B-I extinguishers or one B-II are required to carry.</span>
2/3 is 6sections so if we divide 2/3 by 6 we would find the length of one section.
(2/3)/6=2/18= 1/9
How many 1/9 is equal to 1?
If we multiply 1/9 by 9 we would get 1
So the answer is 9sections