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3 years ago

Find the coordinates of point Q.

Mathematics

1 answer:

Elis [28]3 years ago

6 0

Answer:

Q(2, 6 )

Step-by-step explanation:

Using the midpoint formula

let the coordinates of Q = (x, y ), then

0.5(x + 10) = 6 ( multiply both sides by 2 )

x + 10 = 12 ( subtract 10 from both sides )

x = 2

and

0.5(y + 6) = 6 ( multiply both sides by 2 )

y + 6 = 12 ( subtract 6 from both sides )

y = 6

Coordinates of Q = (2, 6 )

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What integer represents a five-yard law

vovangra [49]

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7 0

3 years ago

A 12-cm-long thin rod has the nonuniform charge density λ(x)=(2.0 nC/cm)e−|x|/(6.0 cm), where x is measured from the center of t

Inessa [10]

Answer:

the total charge is

$Q=24(1-\exp(-1))nC\approx15.171nC$

Step-by-step explanation:

Since x is measured from the center, that means that x=0 is the center so the edges of the rod correspond to x=-6 and x=6. that meas that the total charge can be calculated as

$Q=\int^{6}_{-6}2\exp\left(\frac{-|x|}{6}\right)dx$

separating the integral from -6 to 0 and from 0 to 6, taking into account that |x|=-x for x<0 and |x|=x for x >=0, we get $Q=\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx+\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

using the substitution x=-u in the first integral we get $\int^{0}_{-6}2\exp\left(\frac{x}{6}\right)dx=-\int^{0}_{6}2\exp\left(\frac{-u}{6}\right)du=\int^{6}_{0}2\exp\left(\frac{-u}{6}\right)du$

which is the same as the first integral. Thus, the total charge is given by

$Q=2\int^{6}_{0}2\exp\left(\frac{-x}{6}\right)dx$

integrating we get

$Q=4(-6\exp\left(\frac{-x}{6}\right))\big|^{6}_{0}=-24(\exp(-6/6)-\exp(0))=24(1-\exp(-1))$

4 0

3 years ago

Simplify the following rational expression and express in expanded form.

VladimirAG [237]

Answer:

D m = $-\frac{3}{8}$

Step-by-step explanation:

factor the expressions in the denominator and the numerator to simplify the expression:

=> $\frac{2(-2m + 1)(2m - 1)}{2(2m - 1)(8m + 3)}$

=> $-\frac{2m + 1}{8m + 3}$

to make a fraction undefined, the numerator should be 0, thus, we substitute the values of m from the options into the denominator to make the denominator equals to 0:

=> $-\frac{2m + 1}{8(-\frac{3}{8} ) + 3}$ = $-\frac{2m + 1}{-3 + 3}$ = $-\frac{2m + 1}{0}$