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Fed [463]
1 year ago
11

Please help with segments

Mathematics
2 answers:
Slav-nsk [51]1 year ago
6 0
Yea it’s just 25.5 ads them up just make sure you add the one it talks about like RT if it would of been multiple segments
m_a_m_a [10]1 year ago
4 0
25.5, you need to add the segments together
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Expand and simplify (2x+5y) (x-3y)
Dmitry [639]
Should be simple:

Let's take this one at a time.

2x(x-3y)

You'd get:
2x^2-3xy
for the first one.

2nd one:
5y(x-3y)
you'd get:
+5xy-3y^2

Put them both together:
2x^2-3xy+5xy-3y^2

Combine like terms.

Your Answer:
2x^2+2xy-3y^2

3 0
3 years ago
Number Line<br> B is between A and C. AB= 12 and BC= 17. what is the length of AC?
igor_vitrenko [27]

Answer:

29

Step-by-step explanation:

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3 years ago
Pete and his sister, Sophie, play the game Space Mission Commander on their video game console. Pete has already completed 27 mi
kondor19780726 [428]

Step-by-step explanation:

Pete has already completed 27 missions. Pete plans to complete 3 missions per week

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27 - 13 = 5x - 3x

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6 0
2 years ago
What's the nearest hundred thousand to 491,852
kirza4 [7]

500,000 round up from 491,852 to 500,000

3 0
3 years ago
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Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
2 years ago
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