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3 years ago

Two numbers have a sum of 24 and a product of 143. What is the smaller number?

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

4 0

Answer:

The smaller number is 11.

Step-by-step explanation:

11 + 13 = 24

11 x 13 = 143

Hope this helps!

Masja [62]3 years ago

3 0

The smaller number is 11

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Answer:

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2 years ago

Y = 3x-2 estimate the value of x when y=3

jok3333 [9.3K]

Answer:

x = 5/3

General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

y = 3x - 2

y = 3

Step 2: Solve for x

[Equation] Substitute in y:
3 = 3x - 2
[Addition Property of Equality] Add 2 on both sides:
5 = 3x
[Division Property of Equality] Divide 3 on both sides:
5/3 = x
Rewrite:
x = 5/3

∴ the value of x when y = 3 is equal to 5/3, or approximately 1.67.

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Learn more about Algebra I: brainly.com/question/27710551

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Topic: Algebra I

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2 years ago

Make 6 prime number using 1,2,3,4,5,6,7,8,9

Crazy boy [7]

Answer:

13,67,29,17,19,23

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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neonofarm [45]

Answer:

1) $\frac{\sin x}{1-\cos x} = \csc x + \cot x$

2) $\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}$

3) $\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}$

4) $\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}$

5) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}$

6) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}$

7) $\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}$

Step-by-step explanation:

Now we proceed to show all steps needed to demonstrate the trigonometric identity:

1) $\frac{\sin x}{1-\cos x} = \csc x + \cot x$ Given.

2) $\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}$ Identities for cosecant and cotangent functions.

3) $\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}$ $\frac{a}{b}+\frac{c}{b} = \frac{a+c}{b}$

4) $\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}$ Existence of additive inverse/Modulative property.

5) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}$ Fundamental trigonometric identity.

6) $\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}$ Factorization.

7) $\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}$ Existence of additive inverse/Modulative property/Result.

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3 years ago