Answer:
This college library would hold approximately ![6*10^{5}/tex] books.Step-by-step explanation:Having books on both sides, and each book being 25 centimeters (there is 100 cm in a meter, so 25 cm=0.25 m) deep, shelves must be around 50 cm (or 0.5 m) wide.If corridors must be 1,5 m wide, every two linear meters (perpendicular to corridors and shelves) of floor space there is 1.5 m of corridors and 0.5 m of shelves and that sequence repeats itself, i.e. there is 75% (1.5 of every 2 meters) of space occupied by corridors and 25% (0.5 of every 2 meters) occupied by shelves, that is:[tex]Floor space_{shelves}=Total floor space*proportion of shelves=3500m^{2} *0.25=875m^{2}](https://tex.z-dn.net/?f=6%2A10%5E%7B5%7D%2Ftex%5D%20books.%3C%2Fp%3E%3Cp%3EStep-by-step%20explanation%3A%3C%2Fp%3E%3Cp%3EHaving%20books%20on%20both%20sides%2C%20and%20each%20book%20being%2025%20centimeters%20%28there%20is%20100%20cm%20in%20a%20meter%2C%20so%2025%20cm%3D0.25%20m%29%20deep%2C%20shelves%20must%20be%20around%2050%20cm%20%28or%200.5%20m%29%20wide.%3C%2Fp%3E%3Cp%3EIf%20corridors%20must%20be%201%2C5%20m%20wide%2C%20every%20two%20linear%20meters%20%28perpendicular%20to%20corridors%20and%20shelves%29%20of%20floor%20space%20there%20is%201.5%20m%20of%20corridors%20and%200.5%20m%20of%20shelves%20and%20that%20sequence%20repeats%20itself%2C%20i.e.%20there%20is%2075%25%20%281.5%20of%20every%202%20meters%29%20of%20space%20occupied%20by%20corridors%20and%2025%25%20%280.5%20of%20every%202%20meters%29%20occupied%20by%20shelves%2C%20that%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DFloor%20space_%7Bshelves%7D%3DTotal%20floor%20space%2Aproportion%20of%20shelves%3D3500m%5E%7B2%7D%20%2A0.25%3D875m%5E%7B2%7D)
Knowing that every square meter of floor space occupied by shelves is in reality eight (because of being 8 shelves high) square meters of shelve space where to put books and that the average area of a book is
![Area occupied=depth*width=0.25m*0.05m=0,0125m^{2} per book](https://tex.z-dn.net/?f=Area%20occupied%3Ddepth%2Awidth%3D0.25m%2A0.05m%3D0%2C0125m%5E%7B2%7D%20per%20book)
Having all the necessary data, we estimate how many books would this college library hold:
![Books=\frac{Shelve space}{area_{book} } =\frac{875m^{2}*8 }{0.0125\frac{m^{2} }{book} } =560000 books](https://tex.z-dn.net/?f=Books%3D%5Cfrac%7BShelve%20space%7D%7Barea_%7Bbook%7D%20%7D%20%3D%5Cfrac%7B875m%5E%7B2%7D%2A8%20%7D%7B0.0125%5Cfrac%7Bm%5E%7B2%7D%20%7D%7Bbook%7D%20%7D%20%3D560000%20books)
As it is an estimate, we round it up to the nearest hundred-thousand, i.e., approximately [tex]6*10^{5}/tex] books can be shelved on this library
Answer:
1) Volume of prism is (V=Area of base×Height)
Volume " " "(V=22÷7×rsquare×h)
Answer:did you get the answer to this yet ?
Step-by-step explanation:
Answer:
(c) y>=4
y<x+5
Step-by-step explanation:
The ordered pair (0,4) is a solution
We check with each inequality, and find which inequalities makes it true
(a) y<=4
y>=x+5
Lets plug in x=0 and y=4
4<=4 its true
4 >=0+5 ---> 4>=5 its false
Both inequalities does not satisfies
(b) y<4
y<x+5
Lets plug in x=0 and y=4
4<4 its false
4 <0+5 ---> 4<5 its true
Both inequalities does not satisfies
(c) y>=4
y<x+5
Lets plug in x=0 and y=4
4>=4 its true
4 <0+5 ---> 4<5 its True
Both inequalities satisfies