$\log_ab=c\iff a^c=b\qquad(*)\\\\\log_ab^c=c\cdot\log_ab\qquad(**)\\\\---------------------\\\\\log_3x^6=12\qquad\text{use}\ (**)\\\\6\log_3x=12\qquad\text{divide both sides by 6}\\\\\log_3x=2\qquad\text{Use}\ (*)\\\\3^2=x\to\boxed{x=9}$

8 0

3 years ago

Joseph drove to Carly's house for dinner. He was away from his house for 2 hours. He spent 50 minutes at Carly's house. Driving

kolezko [41]

Answer:

I'd say about 30 minutes away

Step-by-step explanation:

8 0

3 years ago

H(x) = 3x - 1; Find h(3)

vfiekz [6]

Answer:

it is 8 if i substitute x for 3

Step-by-step explanation:

7 0

3 years ago

How can I rewrite this in exponential form and then evaluate it?

Vedmedyk [2.9K]

QUESTION:- EVALUATE THE EXPRESSION

EXPRESSION:-

${( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}$

<h3>ANSWER-></h3>

${( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2} \\ {( {27 {a}^{3} {b}^{4} } )}^{ \frac{2}{6} } \\ {({27 {a}^{3} {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \: 3} } } \\ {(27)}^{ \frac{1}{3} } {a}^{ \frac{3}{3} } {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} } {a}^{ \frac{ \cancel3}{ \cancel3} } {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} } {b}^{ \frac{1}{3} }$ $\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }$

6 0

3 years ago