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3 years ago

5

Write the first expression in terms of the second if the terminal point determined by t is in the given quadrant.

1 answer:

disa [49]3 years ago

8 0

Wat is the first and second terminal point

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Write the word sentence as an equation. Then solve the equation.

telo118 [61]

15x=-75
The answer is would be -5 because -75/15 equals -5

6 0

3 years ago

Read 2 more answers

Help me out some one

Olegator [25]

Y = mx + b is the slope-intercept form of the equation of a line,
where m = slope, and b = y-intercept.

In problems 1 and 3, your equations are written in the y= mx + b form, so you can read the slope and y-intercept directly.

1.
m = -5/2
b = -5

3.
m = -1
b = 3

5.
For problem 5, you need to solve for y to put the equation
in y = mx + b form. Then you can read m and b just like we did
for problems 1 and 3.

4x + 16y = 8

16y = -4x + 8

y = -4/16 x - 8/16

y = -1/4 x - 1/2

m = -1/4

b = -1/2

7 0

4 years ago

In triangle xyz what is the cosine ratio of angle x

Jobisdone [24]

<span>Data:
</span><span>Hypotenuse is 7.5
Opposite of angle x is 6</span><span>

Cosine = Side opposite (S.O) the angle on the hypotenuse (h)

We have:

</span> $Cos (\alpha)x = \frac{S.O}{h}$
$Cos (\alpha)x = \frac{6}{7.5}$
$\boxed{Cos (\alpha)x = 0.8}$

<span>For better understanding, see the annex:

</span>

6 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

Find the perimeter of the right triangle. If necessary, round to the nearest tenth.

Inga [223]

Answer:

B. 36 yd

Step-by-step explanation:

I calculated it logically

6 0

3 years ago