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postnew [5]
3 years ago
13

NEED ANSWER ASAP WILL GIVE THANKS + BRAINLIEST

Mathematics
2 answers:
choli [55]3 years ago
7 0

Answer:

\sf{f(x)=2x^{2}-3x+1}

We have to evaluate this following equation .

f(x)=2x^2-3x+1\\\\f(1)=2(1)^2-3(1)+1\\\\f(1)=2-3+1\\\\f(1)=3-3\\\\f(1)=0

\\\\\\

f(x)=2x^2-3x+1\\\\f(2)=2(2)^2-3(2)+1\\\\f(2)=8-6+1\\\\f(1)=9-6\\\\f(1)=3

il63 [147K]3 years ago
4 0

\\ \sf\longmapsto f(x)=2x^2-3x+1

\\ \sf\longmapsto f(1)=2(1)^2-3(1)+1

\\ \sf\longmapsto f(1)=2(1)-3+1

\\ \sf\longmapsto f(1)=0

Now

\\ \sf\longmapsto f(2)=2(2)^2-3(2)+1

\\ \sf\longmapsto f(2)=2(4)-6+1

\\ \sf\longmapsto f(2)=8-5

\\ \sf\longmapsto f(2)=3

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