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marysya [2.9K]
3 years ago
8

I NEED HELP URGENT! WILL GIVE BRAINLIEST

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Part A

Let <u>at-store</u> service be x

Let <u>on-site</u> service be 3x

Let <u>by-mail</u> service be x - 10

Part B

15 services on-site

40 services at-store

5 services by-mail

Total sales = $2650

∴ 15(3x) + 40(x) + 5(x-10) = 2650

Simplify

15(3x) + 40(x) + 5(x-10) = 2650

45x + 40x + 5x - 50 =2650

90x = 2700

90x/90 = 2700/90

x = 30

Part C

Since x = 30 and services on-site = 3x we can now solve for on-site

on-site = 3x = 3(30) = 90

On-site 1 repair cost $90

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(x,y,z)=(1477, 1464, 1437)

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<h3>Case-1:</h3>
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So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
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2x   - 3y  +  z = 0

<h3>Case-3:</h3>
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- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

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we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

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Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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