The answer to 100.5 divided by 1.5 is 67
200*(107%)^x
x is the number of quarters that passed.
each year has 4 quarters, so 12 yaers would have: 12*4 = 48 quarters
200*(107%)^48 = 5146
For each if the differential equation given in Exercises 1 to 12 find the General Solution. xLogx

+y =

Logx...... Hope This Helps
Step-by-step explanation/Answer:
<u><em>The value for h(3) is 1.</em></u>
<u><em>Coordinate (3,1)</em></u>
The value on h(3) is located in the last part of the piecewise function, which starts at (1,3) until (4,0). To know the exact image of h(3), we can find the function that belongs to that piece of line, and then calculated the asked value.
So, to calculate the equation, we first have to find the slope with its definition, and then we'll use the point-slope formula to find the equation:
<u><em>Therefore, the coordinates is (3,1), that is, the value for h(3) is 1.</em></u>
Answer: 
Step-by-step explanation:
Given
String of the kite is 
Angle of elevation 
suppose altitude of the kite is h
from the figure, we can write

Thus, the altitude of the kite is 