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sveticcg [70]
2 years ago
10

Help me on 1. Please

Mathematics
1 answer:
ratelena [41]2 years ago
3 0
Haha Aaaaaaaaaaaaaaaaaaa
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The answer is 3 at least thats what ive learned
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3 years ago
Factor 200t + 8t 3 - 80t 2. 8t(t - 5)(t + 5) 8t(t - 5)2 -8t(t - 5)(t + 5)
amid [387]
200t + 8t^3 - 80t^2

8t(25 + t^2 - 10t) ....rearrange
8t(t^2 - 10t + 25)
8t(t - 5)(t - 5) 
8t(t - 5)^2 <==
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2 years ago
A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1250 pou
Masja [62]
The forces result in a right triangle. To obtain the resultant force, one can simply use the Pythagorean theorem. 1250 lbf and 2650 lbf both act as the legs of the triangle. Obtaining the hypotenuse via the theorem would yield the resultant force. This is done below:

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Therefore, the magnitude of the resultant force is approximately equal to 2930 lbf.
8 0
3 years ago
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Write the equation of the parabola that has the vertex at point (2,-11) and passes through the point (0,5).
aleksandr82 [10.1K]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{(\stackrel{h}{2}~~,~~\stackrel{k}{-11})}\qquad y=a(x-2)^2-11\qquad \qquad \textit{we also know that} \begin{cases} x=0\\ y=5 \end{cases} \\\\\\ 5=a(0-2)^2-11\implies 16=4a\implies \cfrac{16}{4}=a\implies 4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=4(x-2)^2-11~\hfill

7 0
2 years ago
Which is the solution to this system of equations?
DENIUS [597]
The 1st one is the one that is the Answer
7 0
3 years ago
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