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-BARSIC- [3]
3 years ago
10

A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for the center of the circle and the length

of the radius?
Mathematics
2 answers:
Contact [7]3 years ago
7 0
 <span> x2 + y2 – x – 2y – = 0. 
</span><span>x2  – x  +y2– 2y – = 0. 
</span>(x2  – x +1/4) +(y2– 2y+1) =1/4 +1
(x-1/2)^2+(y-1)^2=1/2+5/2
(x-1/2)^2+(y-1)^2=3/2
center (1/2,1)
radiusSqrt 3/2

madreJ [45]3 years ago
6 0
X^2 + y^2 - x - 2*y = 0
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2

x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4

coordinates of center are (1/2,1) and the radius is √\frac{5}{4}
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natita [175]
That makes 55200*0.62=34224 people.
So 34224 people voted.
3 0
3 years ago
Read 2 more answers
Zak and Ryan earn $60 per week for delivering pizzas. Zak worked for x weeks and earned an additional total bonus of $25. Ryan w
Inessa05 [86]

Answer:

60x + 25 + 60y

Step-by-step explanation:

60 times x plus 60 times y plus 25

4 0
3 years ago
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Is (10, 5) a solution to this system of inequalities? <br><br> 20x + 4y &gt; 5 <br> x + y &lt; 15
Sergio039 [100]
No, it is not a solution, as 15 is not less-than fifteen.<span />
8 0
3 years ago
Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se
kolbaska11 [484]

Answer:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

Step-by-step explanation:

Given:

The expression to expand is given as:

(x-3)(x-9)(x-4)

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

(a + b)(c + d) = ac + ad + bc + bd

(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)

Therefore, the equivalent expression after expanding is given as:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

3 0
3 years ago
can anyone help me out here? I will pay you 20 points
Cerrena [4.2K]

Answer:

The ordered pair that makes an equation true is called a solution

a)solution

b) not a solution

c) solution

d) solution

e)not a solution

f) not a solution

g) solution

h) not a solution

Step-by-step explanation:

The first number in an ordered pair is x, the second one is y

Plug in the numbers to x and y respectively

I'll give two examples so you know how to solve it

a) y=3x+1

-5=3(-2)+1

make sure you use pemdas (multiply first)

-5=-6+1

add

-5=-5

this is true (meaning it is a solution)

b) 6=3(-3) +1

6=-9+1

6 = -8

this is NOT true (not a solution)

If you have any questions feel free to ask

8 0
3 years ago
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