A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for the center of the circle and the length
2 answers:
X^2 + y^2 - x - 2*y = 0
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2
x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4
coordinates of center are (1/2,1) and the radius is √
To find both coordinates and radius we need to make this equation in circle form:
(x-a)^2 + (y-b)^2 = r^2
x^2 - 2*1/2*x + 1/4 - 1/4 + y^2 - 2*1*y + 1 - 1 = 0
Here we are adding and subtracting numbers in order to get square binomial.
(x - 1/2)^2 + (y-1)^2 = 5/4
coordinates of center are (1/2,1) and the radius is √
You might be interested in
Answer: Order will be F,D,C and Fourth Option is correct and x = 10
Step-by-step explanation:
Since we have given that
We first transpose the square root to the right , so it becomes square of 8,i.e.
Now, transpose 4 to the right so it will get subtract from 64 i.e.
Since 6 is multiplied to x on tranposing it will get divided by 60 i.e.
Hence, on simplification, we get x=10.
Hence , the order is F,D,C.
