Dos niños brincan en dos trampolines. El primer niño rebota 1.5 veces más alto que el segundo. La rapidez inicial del segundo ni
1 answer:
Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.
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- Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.
El primer niño rebota <u>1.5 veces más alto que el segundo</u>.
O sea:
La rapidez inicial del segundo niño es de 3.3 m/s.
Esto implica que
¿Cuál es la rapidez (m/s) inicial del primer niño?
La rapidez inicial del primer ninõ es 4.95 m/s.
Un problema similar es dado en brainly.com/question/24646137
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The dimensions of the rectangle are: b=9.65 cm and h=4.35 cm or b=4.35 cm and h= 9.65 cm.
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The question gives:
Perimeter=28cm
Area= 42 cm²
If the perimeter is the sum of all sides of the rectangle, you have:
Perimeter= 2b+2h=28
If the area of the rectangle is 42cm², you have:
Area=bh=42 cm²
You can write a system of linear equations.
2b+2h=28 (1)
bh=42 (2)
From equation 2, you have . Then, you can replace it in equation 1.
Now, you should solve the quadratic equation.
If h1=9.65 cm, then , and if h2=4.35 cm, then
.
Read more about the quadratic function here:
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