H ( x ) = - 6 + x
m = 1 ( the slope )
b = - 6 ( y - intercept )
x - intercept:
0 = - 6 + x
x = 6
The graph is going through Quadrants: I, II and IV.
Answer:
B ) Quadrant II, because the slope is positive and y-intercept is negative.
36/19
=1.894736842 and it keeps going
Hope this helped and have a great day!
Cos9x - cos5x = -2sin2x.sin7x
sin17x - sin3x = 2sin7x.cos10x
so f(x) =

=
Answer:
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Step-by-step explanation:
For this case we have the following 5 number summary from the data of 144 values:
Minimum: 9 days
Q1: 18 days
Median: 21 days
Q3: 28 days
Maximum: 56 days
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Answer:
204
Step-by-step explanation:
Find the area of the inner square. 14 x 14 = 196
Then find the area of the outer square. 20 x 20 = 400
Subtract 400 - 196 = 204
204 is closest to 200