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Mariulka [41]
3 years ago
9

If a book has a a mass of 2 kg, how much does the book weigh?

Physics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

A. 20 N

Explanation:

weight of book is 2×10=20N

You might be interested in
Select the correct answer.
polet [3.4K]

A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?

Choose: 100 kilometers/hour south

6 0
3 years ago
Read 2 more answers
if a body of mass 2kg moving with Velocity of 15m/s collides with a stationary body of same mass then after elastic collision 2n
pochemuha

Answer:

v = 15 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

P=m*v

where:

P = linear momentum [kg*m/s]

m = mass = 2 [kg]

v = velocity = 15 [m/s]

P=2*15\\P=30 [kg*m/s]

Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.

30=2*v\\v = 30/2\\v = 15 [m/s]

5 0
3 years ago
The greater the force exerted by the engine of a car over a set distance, the greater the change in ?
aleksandrvk [35]
The greater the change in velocity, or speed. 
8 0
4 years ago
How much time would it take for the sound of thunder to travel 2000 meters of sound travels at the speed of 330 meters per secon
SpyIntel [72]

Time = (distance covered) / (speed)

Time = (2,000 m) / (330 m/s)

<em>Time = 6.06 seconds</em>

5 0
4 years ago
A circular wire loop of radius 14.1 cm carries a current of 2.34 A. It is placed so that the normal to its plane makes an angle
Tomtit [17]

Answer:

(a)  0.1460Am^2

(b) 1.3927 Nm

Explanation:

We have given that radius r=14.1cm=0.141m

Current i = 2.34 A

Angle \Theta =49.2^{\circ}

Uniform magnetic field B = 12.6 T

Area is given by A=\pi r^2=3.14\times 0.141^2=0.0624m^2

(A) We know that magnetic dipole moment is given by M=iA , here i is current and A is area

So magnetic moment M=iA=2.34\times 0.0624=0.1460Am^2

(b) We know that torque is given by

\tau =BIAsin\Theta

So torque experienced by coil will be \tau =BIAsin\Theta =12.6\times 2.34\times 0.0624\times sin49.2^{\circ}=1.3927Nm

7 0
3 years ago
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