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SashulF [63]
2 years ago
10

Slope of the line (15,20),(-1,11)

Mathematics
1 answer:
masya89 [10]2 years ago
7 0

Answer:

Slope, Angle, & Distance:

Slope: 0.5625

The slope of the line connecting (15, 20) and (-1, 11) is 0.5625

Slope (m): 0.5625

Angle (θ): 29.3578°

Distance: 18.3576

Δx: 16

Δy: 9

Slope Intercept Form:

(y = mx + b)

y = 0.5625x + 11.5625

Step-by-step explanation:

Steps to Find Slope

Start with the slope formula

m=

(y2 - y1)

(x2 - x1)

Substitute point values in the formula

m=

(11 - 20)

(-1 - 15)

Simplify each side of the equation

m=

(11 - 20)

(-1 - 15)

=

-9

-16

Solve for slope (m)

m=0.5625

<h2><em><u>Brainliest?</u></em></h2>
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Dahasolnce [82]

The value of y when x= 2401 is -10

<h3>How to determine the value of x?</h3>

An inverse variation is represented as:

y = \frac{k}{\sqrt x}

Where k is the proportionality constant

When y = -70, x = 49

So, we have:

-70 = \frac{k}{\sqrt {49}}

Take the square root of 49

-70 = \frac{k}{7}

Multiply through by 7

k = -490

Substitute k = -490 in y = \frac{k}{\sqrt x}

y = -\frac{490}{\sqrt x}

When x =2401, we have

y = -\frac{490}{\sqrt {2401}}

Evaluate the square root

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2 years ago
HELP Use either law of sines or law of cosine. Need help on this problem! show work please!​
Marina86 [1]

Answer: x = 15.035677095729 approximately

Round this however you need to.

=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

sin(Q)/PR = sin(R)/PQ

sin(Q)/13 = sin(85)/19

sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

Q = 42.9693397461 ... or ... Q = 137.0306602539

These values are approximate.

----------------

Now if Q = 42.9693397461 approximately, then angle P is

P = 180-Q-R

P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

P = 180-Q-R

P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

sin(P)/p = sin(R)/r

sin(P)/QR = sin(R)/PQ

sin(52.0306602539)/x = sin(85)/19

19*sin(52.0306602539) = x*sin(85)

19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

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Answer:

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