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vovangra [49]
3 years ago
15

Which of the following pair of sets is an example of disjoint sets?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0

We want to see which pair of sets is disjoint, this is, see which pair of sets does not share any element.

The correct option is: <em> E = {even numbers} and F = {odd numbers}</em>

So we only need to see which one is the pair of sets that does not share any element, so we can analyze the given options and see if we can find a number that belongs to both sets.

1) <em>X = {rational numbers} and Y = {whole numbers}</em>

Any whole number is also a rational number, for example:

2 = 4/2

So we can write the number 2 as a quotient of two integers, then we can see that these sets share elements.

2) <em>P={multiples of 2} and Q={multiples of 3}</em>

The number 6 is a multiple of both 2 and 3, thus the number 6 belongs to bot sets, then the sets are not disjoint.

3) <em>G={multiples of 5} and H={multiples of 10}</em>

10 is a multiple of 10 and 5, so the number 10 belongs to both sets, thus the sets are not disjoint.

4) E={even numbers} and F={odd numbers}

We define the even numbers as the ones divisible by 2, while the odd numbers are those that are not divisible by 2. Then by definition, there is no even number that is also odd.

Then we can see that these two sets are disjoints, and this is the correct option.

If you want to learn more, you can read:

brainly.com/question/13143676

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4(3x^2y^4)^3 / (2x^3y^5)^4
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Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

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