V = (pi) * r^2 * h
h = 7
V = 252(pi)
252(pi) = r^2 * 7
252(pi) / 7 = r^2
36(pi) = r^2
sqrt 36(pi) = r
6 = r <==== radius is 6 cm
Answer:
Equation C: 5/8x + 2..5 = 3/8x + 1.5 + 1/4x
Step-by-step explanation:
Let us go through each of the equations one by one.
Equation A: ![2.3y+2+3.1y=4.3y+1.6+1.1y+0.4](https://tex.z-dn.net/?f=2.3y%2B2%2B3.1y%3D4.3y%2B1.6%2B1.1y%2B0.4)
This simplifies to
![5.4y+2=5.4y+2](https://tex.z-dn.net/?f=5.4y%2B2%3D5.4y%2B2)
which has infinitely many solutions.
Equation B: ![32x+25-21x=10x](https://tex.z-dn.net/?f=32x%2B25-21x%3D10x)
this simplifies to
![x+25=0](https://tex.z-dn.net/?f=x%2B25%3D0)
![x=-25](https://tex.z-dn.net/?f=x%3D-25)
which is exactly one solution.
Equation C: ![\frac{5}{8} x+2.5=\frac{3}{8}x+1.5+\frac{1}{4} x](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D%20x%2B2.5%3D%5Cfrac%7B3%7D%7B8%7Dx%2B1.5%2B%5Cfrac%7B1%7D%7B4%7D%20x)
this simplifies to
![\frac{5}{8} x+2.5=\frac{5}{8} +1.5](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B8%7D%20x%2B2.5%3D%5Cfrac%7B5%7D%7B8%7D%20%2B1.5)
![2.5=1.5](https://tex.z-dn.net/?f=2.5%3D1.5)
There's no way this is going to be possible; this equation has no solutions.
Equation D: ![\frac{1}{3} x+\frac{1}{7} x=\frac{3}{7} x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20x%2B%5Cfrac%7B1%7D%7B7%7D%20x%3D%5Cfrac%7B3%7D%7B7%7D%20x)
this gives
![\frac{1}{3} =\frac{2}{7} y](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%3D%5Cfrac%7B2%7D%7B7%7D%20y)
![y=\frac{7}{6}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B7%7D%7B6%7D)
which is exactly one solution.
Thus we see that it is equation C that has no solutions.
Answer:
I believe it would be 4x-8=-3x+13
0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters