(9x^4-13x^3-x-7)+(7x^3-2x+1)=
9x^4-13x^3-x-7+7x^3-2x+1=
9x^4+(-13+7)x^3+(-1-2)x-7+1=
9x^4+(-6)x^3+(-3)x-6=
9x^4-6x^3-3x-6
Answer: Option <span>D.)9x^4−6x^3−3x−6</span>
The information about the points being vertices that make up a line to represent the side of a hexagon is irrelevant, as we are only looking for the distance of a line based on their x and y coordinates.
Look at the point's x and y coordinates:
First point:
x = -5, y = 6
Second point:
x = 5, y = 6
You'll notice that the y-coordinate for both points is the same (6 = 6). This means that the segment created by the points will be horizontal, since there is only movement on the x-axis if you trace the segment from point to point.
To find the distance between the two points, we'll only need to subtract the first point's x-coordinate from the second:
5 - (-5) = 5 + 5 = 10
The answer will be the following statement:
Since the y-coordinates are the same, the segment is horizontal, and the distance between the points is 10 units.
1.No denominator contains a radical.
2.no radicand contains a fraction
Answer:
2.99 cm
Step-by-step explanation:
V= 
(pi)(r^3)=113.04cm^3
113.04/ (pi) = r^3 = 26.99
r=![\sqrt[3]{26.99}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B26.99%7D)
= 2.99cm
<span> x-1+4+7x-3
</span>x+7x-3<span>-1+4
8x-4+4
8x
:)
</span>
