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2 years ago

4. The first two numbers in a sequence are 3, 9.

Mathematics

2 answers:

likoan [24]2 years ago

8 0

Answer:

234567

Step-by-step explanation:

gavmur [86]2 years ago

5 0

Answer:

AP equation:

$t_n=t_1+(n-1)d$

Based on the first two terms, we have:

$t_1=3,\\t_2=9\\d=9-3=6$

The equation is:

$t_n=3+(n-1)*6=3+6n-6=6n-3$

Next two terms are:

$t_3=6*3-3=15\\t_4=6*4-3=21$

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3 years ago

Find the amount in the bank after 7 years if interest is compounded quarterly?

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Answer:

a) amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

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We are given:

Principal Amount P= 5000

Rate r= 4% = 0.04

time t = 7 years

The formula used is: $A=P(1+\frac{r}{n})^{nt}$

where A is future value, P is principal amount, r is rate, n is compounded value and t is time

a) Find the amount in the bank after 7 years if interest is compounded quarterly?

If interest is compounded quarterly then n = 4

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{4})^{4*7} \\A=5000(1+0.01)^{28}\\A=5000(1.01)^{28}\\A=5000(1.321)\\A=6,605$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,605

b) Find the amount in the bank after 7 years if interest is compounded monthly?

If interest is compounded quarterly then n = 12

Using values given in question and finding A

$A=P(1+\frac{r}{n})^{nt}\\A=5000(1+\frac{0.04}{12})^{12*7} \\A=5000(1+0.003)^{84}\\A=5000(1.003)^{84}\\A=5000(1.322)\\A=6,612.57$

So, amount in the bank after 7 years if interest is compounded quarterly is $6,612.57

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2 years ago

Please help! Camille is saving for a laptop that costs about $850. To model her savings plan and determine how many more months

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