H=0
Therefore:
144t-16t²=0
t (144-16t)=0
We have two equations:
1)
t=0 (when the ball is released)
2)
144-16t=0
-16t=-144
t=-144 / -16=9 (this is the time )
Answer: the ball hit the ground in 9 s.
Answer:
X= -7/6, 17/8
Step-by-step explanation:
Foil it, then use quadratic to find zeros/roots.
Vcylinder=hpir^2
Vsphere=(4/3)pir^3
Vcone=(1/3)hpir^2
Vcylinder=15*pi*5^2=375pi in^3
Vsphere=(4/3)*pi*6^3=288pi in^3
Vcone=(1/3)*15*pi*8^2=320pi in^3
greatest is Vcylinder at 375pi in^3
answer is A (cylinder)
Answer:
14) 2x + 13 = 21
Step-by-step explanation:
Have a nice day! :-)
Image is missing, so i have attached it.
Answer:
AC = 10sin 40°
Step-by-step explanation:
From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.
Thus, since we want to find AC;
We know that in trigonometric ratios; opposite/hypotenuse = sin θ
In the diagram, θ = 40° and AB = 10
Thus,
AC/10 = sin 40°
Multiply both sides by 10 to get;
AC = 10sin 40°