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3 years ago

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A rectangular region of land in a state park has a length of 10,000 meters and a width of 4.8 × 10^3 meters. What is the area of

the land in square meters? Write the answer in scientific notation.
_____ square meters

1 answer:

Leona [35]3 years ago

8 0

95

Step-by-step explanation:

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What is the value of x in the figure?<br><br> Enter your answer in the box

Tcecarenko [31]

Answer:

x =68

Step-by-step explanation:

We know that x+22 = 90 because the sum of the two angles is a vertical angle to the right angle and vertical angles are equal.

x+22 =90

Subtract 22 from each side

x+22-22 = 90-22

x =68

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3 years ago

What is the area of the hexagon below?

sergejj [24]

Answer:

14m^2

Step-by-step explanation:

To find the area of this hexagon, you should separate this shape into 2 other shapes.

You can see that there is a parallelogram, and a rectangle shape within this hexagon, so you can find the area of these 2 shapes and later on, just add it.

The area of this rectangle is...

width✖️height: 6✖️2=12

The area of this parallologram is...

base✖️height: 6✖️2=12

12+12=14m^2

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3 years ago

4xsquared - 9=0? could anyone help me solve this quadratic equation by FACTORING?

Verizon [17]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
4x^2-9=0\implies 2^2x^2-3^2=0\implies (2x)^2-3^2=0
\\\\\\\
[(2x)-3][(2x)+3]=0\implies 
\begin{cases}
2x-3=0\\
2x=3\\
x=\frac{3}{2}\\
------\\
2x+3=0\\
2x=-3\\
x=-\frac{3}{2}
\end{cases}$

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3 years ago

Evaluate 3(a-4b) when a= -2 and b= 5

pshichka [43]

I believe the answer is -26 :) I hope this helps! ^_^

7 0

3 years ago

In-s [12.5K]

Answer:

1. x = 39.67

2. x = 15

3. x = 49.29

4. x = -12.8

5. x = 96

6. x = 42

7. x = 36

8. x = 0

9. x = 78

Step-by-step explanation:

Just remember to always isolate the unknown. Here are the solutions to your problem. I will explain each step for the first for you to give you an idea how the others were worked out.

1. $\dfrac{3x}{7}-2 = 15$

Add 2 to both sides to get rid of -2 on the left side.

$\dfrac{3x}{7}-2+(2)=15+(2)///dfrac{3x}{7}=17$

Multiply both sides by 7 to get rid of 7 on the left side.

$\dfrac{3x}{7}\times 7 = 17\times 7\\\\3x = 119$

Divide both sides by 3 to get rid of 3 on the left side.

$\dfrac{3x}{3} = \dfrac{119}{3}\\\\x = 39.67$

You could also transpose everything by the x to the other side of the equation. Just remember that whatever OPERATION used on the original side, must be opposite on the other side. I'll use the second problem to show this.

$\dfrac{2x}{5}+1=7$

Transpose 1 on the left to the right. It is addition on the left, then it would be subtraction on the other side.

$\dfrac{2x}{5}+1=7\\\\\dfrac{2x}{5}=7-1\\\\\dfrac{2x}{5}=6$

Transpose 5 from the left side to the right. It is division on the left, then it would be multiplication on the right.

$\dfrac{2x}{5}=6\\\\2x=6\times 5\\\\2x=30$

Transpose 2 from the left side to the right. It is multiplication on the left, then it would be division on the right.

$2x=30\\\\x=\dfrac{30}{2}\\\\x=15$

Let's move on with the rest now.

3.

$\dfrac{7x}{15}-1=22\\\\\dfrac{7x}{15}=22+1\\\\\dfrac{7x}{15}=23\\\\7x=23\times15\\\\7x=345\\\\x=\dfrac{345}{7}\\\\x=49.29$

4.

$\dfrac{5x}{8}+10=2\\\\\dfrac{5x}{8}=2-10\\\\\dfrac{5x}{8}=-8\\\\5x=-8\times8\\\\5x=-64\\\\x=\dfrac{-64}{5}\\\\x=-12.8$

5.

$\dfrac{x}{6}+4=20\\\\\dfrac{x}{6}=20-4\\\\\dfrac{x}{6}=16\\\\x=16\times6\\\\x=96$

6.

$\dfrac{x}{3}-4=10\\\\\dfrac{x}{3}=10+4\\\\\dfrac{x}{3}=14\\\\x=3\times14\\\\x=42$

7.

$\dfrac{x}{6}+2=8\\\\\dfrac{x}{6}=8-2\\\\\dfrac{x}{6}=6\\\\x=6\times6\\\\x=36$

8.

$\dfrac{x}{9}+8=8\\\\\dfrac{x}{9}=8-8\\\\\dfrac{x}{9}=0\\\\x=0\times9\\\\x=0$

9.

$\dfrac{x}{6}+7=20\\\\\dfrac{x}{6}=20-7\\\\\dfrac{x}{6}=13\\\\x=13\times6\\\\x=78$

6 0

3 years ago