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3 years ago

What percent is 272 out of 355?

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

3 0

Answer:

76.62 you might need to round though

Step-by-step explanation:

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If a and b are positive constants and if a(x-y) = b(y-x), what is the value of the ratio of x/y?

Mekhanik [1.2K]

Answer: x/y=1

Step-by-step explanation:

a(x-y)=b(y-x)

(a+b)x=(a+b)y

x/y=1 ans

hope this helps

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3 years ago

Plz don’t be rude if i got brainly i’m gonna use it

SSSSS [86.1K]

Answer:

y=-5x-36

Step-by-step explanation:

-66-(-61)= -5

6-5= 1

-5/1= -5

Y=-5x + B

-66= -5(6) + B

-66= -30 + B

-66 + 30 = (-30 +30) + B

-36 = B

Y= -5x-36

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3 years ago

What is the constant in the expression 12q + 9e + 15

Talja [164]

Answer:

Step-by-step explanation:

the constant in this expression is 15

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3 years ago

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The graph shows the relationship between the number of pizzas and the number of people the pizzas will feed at a party How

Goshia [24]

Answer:

12 homie

Step-by-step explanation:

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3 years ago

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Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago