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FinnZ [79.3K]
3 years ago
7

Whats (c-7)(c+5) , (double brackets)

Mathematics
2 answers:
kherson [118]3 years ago
6 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's evaluate :

  • (c - 7)(c + 5)

  • {c}^{2}  + 5c - 7c - 35

  • {c}^{2}  - 2c - 35
Strike441 [17]3 years ago
5 0

\\ \sf\longmapsto (c-7)(c+5)

\\ \sf\longmapsto c(c+5)-7(c+5)

\\ \sf\longmapsto c^2+5c-7c-35

\\ \sf\longmapsto c^2-2c-35

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{y +2 = 4x<br> {y = 3x - 1
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Evaluate the expression when m= 6.<br> m² - 19
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When dealing with the number of occurrences of an event over a specified interval of time or space, the appropriate probability
sdas [7]

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a)  Poisson distribution

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Step-by-step explanation:

<u> Poisson distribution</u>

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use a  Poisson distribution model when events happen at a constant rate over time or space.

<u>Hyper geometric probability distribution</u>:-

The Hyper geometric probability distribution is a discrete probability distribution that describes the probability of successes (random draws for which the object drawn has a specified feature) in draws without replacement, from a finite population of size that contains exactly objects with that feature where in each draw is either a success or failure.

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<u></u>

<u>Binomial distribution</u>

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3 0
4 years ago
17. A company wanted to determine what percentage of its employees stayed for at least 1, 2, and
Vikki [24]

Answer:

Option B. 0.71

Step-by-step explanation:

There are 200 males and 300 female employees in the company.

The percentage of its employees are given who stayed for at least 1, 2 and 3 years.

                    1 year          2 years          3 years

Male              0.67              0.45             0.20

Female         0.73               0.64              0.39

Number of male employees who stayed at least one year = 0.67 × 200

                                                                                                 = 134

Number of female employees who stayed at least 1 year = 0.73 × 300

                                                                                               = 219

Total employees who stayed at least 1 year = 134 + 219 = 353

Total employees in the company = 200 (males) + 300 (females)

                                                       = 500 employees

Probability that an employee stayed for at least one year = \frac{353}{500}

                                                                     = 0.706 ≈ 0.71

Option B 0.71 is the answer.

8 0
3 years ago
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