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masha68 [24]
3 years ago
7

Y-intercept of -2x+1/2y=18

Mathematics
1 answer:
Pani-rosa [81]3 years ago
8 0
Y=36 is the y-intercept simply substitute 0 as x
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A seasonal index for a monthly series is about to be calculated on the basis of three years’ accumulation of data. The three pre
yarga [219]

Answer:

0.684

Step-by-step explanation:

According to the scenario, computation of the given data are as follows

Seasonal index = Average value for July ÷ Average over all months

Where, Average value for July = ( 110 + 150 + 130 ) ÷ 3

= 390 ÷ 3 = 130

And, average over all months = 190

So by putting the value in the formula, we get

Seasonal index = 130 ÷ 190

= 0.684211 or 0.684

Hence, approximate seasonal index for July is 0.684.

6 0
3 years ago
A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school
nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let p_1 = <u><em>proportion of Illinois high school freshmen who have used anabolic steroids.</em></u>

p_2 = <u><em>proportion of Illinois high school seniors who have used anabolic steroids.</em></u>

SO, Null Hypothesis, H_0 : p_1=p_2      {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, H_A : p_1\neq p_2      {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here <u>Two-sample z test for</u> <u>proportions</u>;

                        T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of high school freshmen who have used anabolic steroids = \frac{34}{1679} = 0.0203

\hat p_2 = sample proportion of high school seniors who have used anabolic steroids = \frac{24}{1366} = 0.0176

n_1 = sample of high school freshmen = 1679

n_2 = sample of high school seniors = 1366

So, <u><em>the test statistics</em></u>  =  \frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }

                                     =  0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0
3 years ago
What percent of 260 is 78
Reptile [31]

If you are using a calculator, simply enter 78÷260×100 which will give you 30 as the answer.

4 0
3 years ago
Read 2 more answers
Please help me with this question
maw [93]
The answer is b with the angles
8 0
3 years ago
A sofa is on sale for 15% off. The sale price is $289.<br> What is the regular price?
PilotLPTM [1.2K]

Answer:

the answer is $332.35 hope this helps

6 0
3 years ago
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