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Over [174]
3 years ago
5

Eight more than the product of a number and 6 is 4. Use the variable w for the unknown number

Mathematics
1 answer:
Anika [276]3 years ago
4 0
W6 + 8 = 4 
w6 = -4 
w = -4/6 
w = -2/3 
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C.is decrease by 1 foot every 500 miles D. Is decrease by 1 foot every 1000 miles
Tasya [4]

Answer:

Option A

Step-by-step explanation:

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

Slope = \frac{y_2-y_1}{x_2-x_1}

Line shown in the graph is passing through two points (2, 8000) and (4, 7000).

Therefore, slope of the given line = \frac{8000-7000}{2-4}

                                                        = -500 feet per mile

Which means, altitude decreases by 500 ft every mile.

(Negative sign represents the decrease)

Option A is the correct option.

4 0
2 years ago
Solve the equation: 5 + 2(3 + 2x) = x + 3(x + 1)
Ann [662]

Answer:

No solutions

Step-by-step explanation:

In this question, you would be solving for x.

Solve:

5 + 2(3 + 2x) = x + 3(x + 1)

Use the distributive property.

5 + 6 + 4x = x + 3x + 3

Combine like terms.

11 + 4x = 4x + 3

Subtract 4x from both sides.

11 = 3

Since we don't have an "x value", there are no solutions.

"No solutions" would be your answer.

5 0
3 years ago
each classroom in willett hall will hold 34 students.There are 4 floors with 6 classroom on each floor. How many students can be
ozzi

4 floors with 6 class rooms each = 6*4 = 24 total class rooms.

24 class rooms x 34 students in each one = 816 total students.

4 0
3 years ago
Read 2 more answers
What is the measurement of this angle
mafiozo [28]

Answer:

28°

Step-by-step explanation:

62° + 90° = 152°

180° - 152° = 28°

Stay safe and have a wonderful day! Peace!✌

6 0
3 years ago
Read 2 more answers
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
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