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3 years ago

Whats the greatest common factor shared by 6 and 60

Mathematics

2 answers:

mezya [45]3 years ago

8 0

Answer:

Step-by-step explanation:

60/6 = 10

6/6 = 1

Step2247 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

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A grading machine can grade 48 multiple choice test in one minute how long will it take the machine to grade 300 hundred

VashaNatasha [74]

Answer:

I believe it would be 14,400

7 0

3 years ago

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What is the range of the given function? {(-2, 0), 6-4, -3), (2, -9), (0, 5), (-5, 7)}

Novosadov [1.4K]

It would be the Ys in the points, the second numbers: 0,-3,-9,5,7

7 0

3 years ago

Please, i need help :(

ollegr [7]

Answer:

First of all, find x from the Pythagorean theorem $a^2+b^2=c^2$ , which c is the hypotenuse.

$7^2+24^2=c^2$

$49+576=c^2$

$c^2=625$

c=25 or x=25

Next, we have to figure out the value of y and z. So, you need to use inverse trigonometric functions.

arctan $(\frac{7}{24})=y=16.3$ degrees. arctan $(\frac{24}{7})=z=73.7$ degrees.

All in all, the values are

x=25

y=16.3

z=73.7

Hope this helps and have a nice day!

7 0

3 years ago

Find the mathematical expression that describes the pattern 3, 7, 11, 15...

cricket20 [7]

Answer:

a+(n−1)d

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5 0

3 years ago

To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To com

Mrrafil [7]

Answer:

$\sigma_1 = 0.08$ --- Location 1

$\sigma_2 = 0.34$ --- Location 2

Step-by-step explanation:

Given

See attachment for the given data

Required

The standard deviation of each location

For location 1

First, calculate the mean

$\bar x_1 =\frac{\sum x}{n}$

So, we have:

$\bar x_1 =\frac{30.40+30.20+30.30+30.40+30.30}{5}$

$\bar x_1 =\frac{151.60}{5}$

$\bar x_1 =30.32$

The standard deviation is calculated as:

$\sigma_1 = \sqrt{\frac{\sum(x - \bar x_1)^2}{n-1}}$

$\sigma_1 = \sqrt{\frac{(30.40 - 30.32)^2+(30.20 - 30.32)^2+(30.30 - 30.32)^2+(30.40 - 30.32)^2+(30.30 - 30.32)^2}{5-1}}$

$\sigma_1 = \sqrt{\frac{0.028}{4}}$

$\sigma_1 = \sqrt{0.007}$

$\sigma_1 = 0.08$

For location 2

First, calculate the mean

$\bar x_2 =\frac{\sum x}{n}$

So, we have:

$\bar x_2 =\frac{30.10+30.90+30.20+30.70+30.30}{5}$

$\bar x_2 =\frac{152.2}{5}$

$\bar x_2 =30.44$

The standard deviation is calculated as:

$\sigma_2 = \sqrt{\frac{\sum(x - \bar x_2)^2}{n-1}}$

$\sigma_2 = \sqrt{\frac{(30.10-30.44)^2+(30.90-30.44)^2+(30.20-30.44)^2+(30.70-30.44)^2+(30.30-30.44)^2}{5-1}}$

$\sigma_2 = \sqrt{\frac{0.472}{4}}$

$\sigma_2 = \sqrt{0.118}$

$\sigma_2 = 0.34$

4 0

3 years ago