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s2008m [1.1K]
3 years ago
14

Please answer this correctly

Mathematics
2 answers:
Vlad [161]3 years ago
3 0

Answer: 1/4

Step-by-step explanation:

The cheesiest recipe would be 1 cup and the least cheesy recipe would be 3/4 cups

1 - 3/4 = 1/4

eimsori [14]3 years ago
3 0

Answer:

\frac{1}{4} cup of cheese

Step-by-step explanation:

The least cheesiest recipe uses \frac{3}{4} cup of cheese while the most cheesiest uses 1 cup of cheese.

1-\frac{3}{4} =\\\\\frac{1}{4}

The most cheesiest uses \frac{1}{4} cup more cheese than the least cheesiest.

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In a bag, Gary has 3 red marbles, 4 blue marbles, 7 yellow marbles, 5 green marbles, 6 purple marbles, and 8 clear marbles. What
miskamm [114]

Answer:

2220

Step-by-step explanation:

gcd of all numbers

3,4,7,5,6,8

2 = 3,2,7,5,3,4

2 = 3,1,7,6,3,2

2 = 3,1,7,5,3,1

3 = 1,1,7,5,1,1

6 0
2 years ago
One number exceeds another by -1. the sum of the numbers is 5. what are the numbers?
maks197457 [2]
X-y=-1
x+y=5
y=x+1
x+x+1=5
2x+1=5
2x=4
x=2
y=x+1
y=2+1
y=3
4 0
3 years ago
Jackrabbits are capable of reaching speeds up to 40 miles per hour. How fast is this in feet per second? (Round to the nearest w
Sonja [21]
To solve this problem, we are going to use a scientific/mathematics strategy called Dimensional Analysis.

40 miles / 1 hour * 5280 feet / 1 mile = 211200 feet / 1 hour

211200 feet / 1 hour * 1 hour / 60 minutes = 3520 feet/ 1 minute

3520 feet / 1 minute * 1 minute / 60 seconds = approximately 59 feet / 1 second


Jackrabbits travel approximately 59 feet per second, when rounded to the nearest whole number.

8 0
3 years ago
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

Solve for u:

\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

so that the particular solution is

y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

3 0
3 years ago
Every weekday, Mr. Jones bikes from his home to his job. Sometimes he rides along two roads, the long route that is shown by the
notka56 [123]

Answer:

(A)6 kilometers

Step-by-step explanation:

First, we determine the value of a using Pythagoras Theorem.

Hypotenuse^2=Opposite^2+Adjacent^2\\17^2=a^2+15^2\\a^2=17^2-15^2\\a^2=289-225\\a^2=64\\a^2=8^2\\a=8$ km

Therefore:

Distance along the long route = 8 + 15 =23 km

Distance along the shortcut =17 km

Difference =23-17 =6km

Therefore, Mr. Jones bikes 6km less when he takes the shortcut instead of the long route.

5 0
3 years ago
Read 2 more answers
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