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3 years ago

A(x-y) + b (x-y) factorize

Mathematics

1 answer:

Andre45 [30]3 years ago

4 0

Answer:Given expression : a(x-y)-b(x-y)

Now, (x-y) is common in both terms.

First factor is (x-y).

∴a(x−y)−b(x−y)=(x−y)(a−b)

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Write two numbers that multiply to −33 and add to 8

cupoosta [38]

Answer:

-3 and 11

Step-by-step explanation:

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2 years ago

A high school athletic department bought 40 soccer uniforms at a cost of $3,000. After soccer season they returned some uniforms

quester [9]

Interesting problem.

First - let's figure cost of each uniform at purchase.

3,000/40 = $75 each

When some uniforms were returned at $40 - there was a difference of $35 in what they paid and what they rec'd in return. ($75 - 35 = $40)

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3 years ago

5x+20y=4<br> x=-4y+1<br><br> Solve for x/y

Andrews [41]

Hi there!

Looks like a lot of work is going on here.

Let's start by solving this equation for the x.

$5x + 20y = 4$

Step 1) Add -20y to both sides.

$5x + 20y + - 20y = 4 - 20y 5x = -20y + 4$

Step 2) Divide both sides by 5.

$\frac{5x}{5} = \frac{-20y + 4}{5}$

$x = -4y + \frac{4}{5}$

Final Answer:

$x = -4y + \frac{4}{5}$

Now, let's solve for y.

Step 1) Add -5x to both sides.

$5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4$

Step 2) Divide both sides by 20.

$\frac{20y}{20} = \frac{-5x + 4}{20}$

$y = \frac{-1}{4} x + \frac{1}{5}$

Final Answer:

$y = \frac{-1}{4} x + \frac{1}{5}$

Hope this helps! :D

Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

6 0

3 years ago

How do I do the algebra problem 5(b-1)?

nirvana33 [79]

Answer:

5b-5

Step-by-step explanation:

When doing these kinds of problems you want to do dributive property which means you multiply whatever number is outside of the (), which is 5, and multiply that by b and 1.

when numbers are outside the () and right next to them without anything like +,-, or a division sign, it means to multiply.

4 0

3 years ago

Read 2 more answers

Simplyfy 8x^4y^5 times 10xy^3

Dennis_Churaev [7]

Answer:

$80x^5y^8$

Step-by-step explanation:

$8x^4y^5\times 10xy^3=\\\\(8\times 10) \times (x^4\times x)\times (y^5\times y^3)=\\\\80x^5y^8$

Hope this helps!

4 0

3 years ago

Read 2 more answers

A(x-y) + b (x-y) factorize​

A(x-y) + b (x-y) factorize