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zmey [24]
2 years ago
15

What’s 36.3 square root than nearest tenth !

Mathematics
1 answer:
pav-90 [236]2 years ago
5 0
So enter, square root sign, then 3.36 under and it gives you 6.04979….. rounded is:

6.0
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Solve the equation. 5x + 8 − 3x = −10 x = −9 x = −1 x = 1 x = 9
vitfil [10]

Answer:

x=-9

Step-by-step explanation:

5x+8-3x=-10

Simplify to get 2x+8=-10

Find what 2x equals to by taking away 8, 2x = -18.

Divide by 2 to find x, x = -9

3 0
4 years ago
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The quotient of 9 and c
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Answer:

The quotient of a number and 9 means n divided 9.

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In eight minutes josh was able to type 496 words what’s he typing speed per minute
zysi [14]

Answer: 62 words per minute.

Step-by-step explanation: 496/8=62.

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A student takes 1/6 hour to paint a picture frame. How many picture frames can the student paint in 4 hours
Sergeeva-Olga [200]

Answer:

24 picture frames

Step-by-step explanation:

Since a student takes 1/6 hour to paint a picture frame, so in an hour, the student will paint a total of 6 picture frames. So to find the number of picture frames in 4 hours, you just need to multiply 4*6 to get 24 picture frames.

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4 years ago
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Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
3 years ago
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