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Kitty [74]
3 years ago
13

Ms. Bustamante collected data on how many years other teachers at school have been teaching. She collected the following data: 1

, 1, 3, 12, 9, 6, 7, 4, 5
Least:

Greatest:

Median:

Lower Q:

Upper Q:
Mathematics
2 answers:
Kobotan [32]3 years ago
5 0
Least:1 greatest:12 Median:5 lower Q:3 upper q:7
Savatey [412]3 years ago
4 0
Least: 1

Greatest: 12

Median: 5

Lower Q: 3

Upper Q: 7
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Confused on what do do first . Can anyone help ?
kirza4 [7]
So solve for q

first factor q out of the summationq \sum^{\inf}_{k=2} (\frac{2}{3})^k=8

now, determine what the summation is
\sum^{\inf}_{k=2} (\frac{2}{3})^k =?

its been a while since ive done summations so i dont remember any tricks but that summation is essentially equal to
\frac{2}{3} ^2 +\frac{2}{3}^3+\frac{2}{3}^4+\frac{2}{3}^5+...

or factored to be something like this
\frac{2}{3}^2 *(1+\frac{2}{3}+\frac{2}{3}^2+\frac{2}{3}^3+...)
which i believe there's a formula for

regardless using a calculator, the summation turns out to be 4/3 i think

you should definitely double check this step

so replacing the summation for 4/3, the equation is now
q*(4/3) =8

pretty easy to solve from here
divide 4/3 to both sides to get q


any questions?
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