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scoundrel [369]
3 years ago
15

HELP ME PLEASE BRAINIEST IF CORRECT BEEN STUCK ON THIS FOR HOURS AND THIS IS DUE AT 11:59pm and it is 11:46pm!!!!

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0

Here's the Answer :

  • A. linear equation

  • B. not a linear equation

  • C. linear equation

  • D. linear equation

  • E. not a linear equation

  • F. linear equation

  • G. not a linear equation

  • H. linear equation

for every linear equation value is 4 and for a non - linear equation value is 12

so, let's solve for the code :

  • \dfrac{12(4+4)+12(12+4-4)}{4}

  • \dfrac{(12×8)+(12×12)}{4}

  • \dfrac{96+144}{4}

  • \dfrac{240}{4}

  • 60
lakkis [162]3 years ago
8 0

Answer:

84

Step-by-step explanation:

A is linear.

B is not linear.

C is linear.

D is linear.

E is not linear.

F is linear.

G is not linear.

H is not linear.

So, solve for \frac{12(4 + 12) + 12(12 + 4 - 4)}{4}, which equals 84.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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3 0
3 years ago
17x - 6 + 3x - 5 = x + 11 + 4x<br> simplify
densk [106]

Answer:

The answer is x= 22/15=1,47

Step-by-step explanation:

We put in one member the X and in the other the whole numbers:

17x - 6 + 3x - 5 = x + 11 + 4x

17x +3x -x-4x= 11+6+5

15x = 22

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7 0
4 years ago
What is the midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i
alexdok [17]

Answer:

Midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

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Step-by-step explanation:

The midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

\dfrac{6-2i-4+6i}{2} \\\\=\dfrac{2+4i}{2}\\ \\=1+2i

Hence, midpoint of a segment in the complex plane with endpoints at 6 -2i and -4 + 6i is:

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5 0
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