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san4es73 [151]
3 years ago
6

What is 3/6 times 2/9

Mathematics
2 answers:
steposvetlana [31]3 years ago
6 0
2 is your answer because 9/18 and 4/18 multiplied by each other = 36/18, which is converted to 2.
Readme [11.4K]3 years ago
6 0

Answer:

its 1/9 with a repeating decimal of 0.11111....

Step-by-step explanation:

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What is the answer to the equation7/8(x - 1/2)=-49/80
Anna007 [38]
7/8(x-1/2)=-49/80
70/80(x-40/80)=-49/80     make all common denominator
x-40/80=-56/80                  divide -49/80 by 70/80 to isolate parentheses
x=16/80 or 1/5                   add 40/80 to isolate x

I'm not sure if my answer right because I was rushing but if you follow what I wrote next to the lines you should get the right answer
5 0
3 years ago
Select all that apply.
Burka [1]

For this case we propose a rule of three to obtain the number that represents 25% of 37.

So, we have:

37 --------> 100%

x -----------> 25%

Where "x" is the number that represents 25% of 37.

x = \frac {25 * 37} {100}\\x = 9.25

Finally, we have that 25% of 37 is 9.25.

Answer:

25% of 37 is 9.25.

3 0
3 years ago
Which statements are true about the circle shown below? Select two options.
AfilCa [17]

Answer:

C,D

Step-by-step explanation:

E d g e n u i t y

5 0
3 years ago
Read 2 more answers
What is the mean for the data set?<br> 8 10 6 4<br> 12 6 8 14
Ipatiy [6.2K]

Answer:

<em>8.5</em>

Step-by-step explanation:

To find mean, we simply take the average of all the numbers in the data set, and divide in by the amount of values!

8+10+6+4+12+6+8+14= 68\\

68 ÷ 8 = 8.5!

4 0
3 years ago
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C and D are mutually exclusive events. Find P(C or D).<br> P(C)= 3/7= P(D)= 4/7<br> P(C or D)
IgorLugansk [536]

Answer:

P(C\ or\ D) = 1

Step-by-step explanation:

Given

P(C) = \frac{3}{7}

P(D) = \frac{4}{7}

Required

P(C\ or\ D)

Since the events are mutually exclusive, then:

P(C\ or\ D) = P(C) + P(D)

So, we have:

P(C\ or\ D) = \frac{3}{7} + \frac{4}{7}

Take LCM

P(C\ or\ D) = \frac{3+4}{7}

P(C\ or\ D) = \frac{7}{7}

P(C\ or\ D) = 1

3 0
3 years ago
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