Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Answer:
x2- 2x+1 =x2-x-x+1
=x(x-1) -1(x-1)
=(x-1)(x-1)
We need to keep it this way as this is the simplest way of expressing its factors.
-1
We just have to divide 2,000 by 6
lets do the math:)
2,000 ÷ 6 = 333.333333333
So if we round this it becomes 2
<span>So your answer is B.) 2 </span>
Answer:
Binomial, The degree is 3, The coefficients are -8 & 5, and there are no constants
Step-by-step explanation:
Answer: Girls: 20
Boys: 30
Step-by-step explanation: 40% of 50 is 20, which means there are 20 girls.
Subtract 50-20 to get the number of boys, which is 30.