The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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Answer:
15
Step-by-step explanation:
By the diagram, you can see the sum of segment AB and segment BC is segment AC. Adding the given expressions for AB and B is . Simplifying the equation , gives . Substituting in the equation for segment AC gives 15.
Answer:
the answer is c)SAS
Step-by-step explanation:
as the sides are already given and and both angles will be equal as vertically opposite angles (VOA)are always equal.
V=hpir^2
tricky, they didn't give us radius
they just gave circiufmerece
c=2pir
25.12=2pir
divide by 2 both sides
12.56=pir
divide by 3.14 both sides
4=r
subsitutet
v=hpir^2
v=66pi4^2
v=66pi16
v=1056pi
v=3315.84 cubic inches
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